2[d-(4d+12)+4]=2(d+8)

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Solution for 2[d-(4d+12)+4]=2(d+8) equation:


Simplifying
2[d + -1(4d + 12) + 4] = 2(d + 8)

Reorder the terms:
2[d + -1(12 + 4d) + 4] = 2(d + 8)
2[d + (12 * -1 + 4d * -1) + 4] = 2(d + 8)
2[d + (-12 + -4d) + 4] = 2(d + 8)

Reorder the terms:
2[-12 + 4 + d + -4d] = 2(d + 8)

Combine like terms: -12 + 4 = -8
2[-8 + d + -4d] = 2(d + 8)

Combine like terms: d + -4d = -3d
2[-8 + -3d] = 2(d + 8)
[-8 * 2 + -3d * 2] = 2(d + 8)
[-16 + -6d] = 2(d + 8)

Reorder the terms:
-16 + -6d = 2(8 + d)
-16 + -6d = (8 * 2 + d * 2)
-16 + -6d = (16 + 2d)

Solving
-16 + -6d = 16 + 2d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2d' to each side of the equation.
-16 + -6d + -2d = 16 + 2d + -2d

Combine like terms: -6d + -2d = -8d
-16 + -8d = 16 + 2d + -2d

Combine like terms: 2d + -2d = 0
-16 + -8d = 16 + 0
-16 + -8d = 16

Add '16' to each side of the equation.
-16 + 16 + -8d = 16 + 16

Combine like terms: -16 + 16 = 0
0 + -8d = 16 + 16
-8d = 16 + 16

Combine like terms: 16 + 16 = 32
-8d = 32

Divide each side by '-8'.
d = -4

Simplifying
d = -4

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